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Python 交错合并多个list列表的方法及示例代码示例代码：

代码语言：javascript复制l1 = ["a","b","c","d"]

l2 = [1,2,3,4]

l3 = ["w","x","y","z"]

l4 = [5,6,7,8]实现效果：

代码语言：javascript复制l5 = ["a",1,"w",5,"b",2,"x",6,"c",3,"y",7,"d",4,"z",8]1、直接使用"+"号合并列表代码语言：javascript复制l5 = l1 + l2 + l3 + l4 2、使用extend方法代码语言：javascript复制l5 = l1.extend(l2,l3,l4,l5) 3、使用append方法代码语言：javascript复制aList = [1,2,3]

bList = ['www', 'jb51.net']

aList.append(bList)

print(aList)

# 输出：

[1, 2, 3, ['www', 'jb51.net']]4、使用zip()实现文档：zip()

代码语言：javascript复制l1 = ["a", "b", "c", "d"]

l2 = [1, 2, 3, 4]

l3 = ["w", "x", "y", "z"]

l4 = [5, 6, 7, 8]

l5 = [x for y in zip(l1, l2, l3, l4) for x in y]

print(l5)输出：

代码语言：javascript复制['a', 1, 'w', 5, 'b', 2, 'x', 6, 'c', 3, 'y', 7, 'd', 4, 'z', 8]5、使用itertools.chain() 和 zip()相关文档：itertools.chain 和 zip:

代码语言：javascript复制from itertools import chain

l1 = ["a", "b", "c", "d"]

l2 = [1, 2, 3, 4]

l3 = ["w", "x", "y", "z"]

l4 = [5, 6, 7, 8]

print(list(chain(*zip(l1, l2, l3, l4))))或者代码语言：javascript复制print(list(chain.from_iterable(zip(l1, l2, l3, l4))))6、使用itertools实现文档：itertool recipes

代码语言：javascript复制from itertools import cycle, islice

l1 = ["a","b","c","d"]

l2 = [1,2,3,4]

l3 = ["w","x","y","z"]

l4 = [5,6,7,8]

lists = [l1, l2, l3, l4]

def roundrobin(*iterables):

"roundrobin('ABC', 'D', 'EF') --> A D E B F C"

# Recipe credited to George Sakkis

num_active = len(iterables)

nexts = cycle(iter(it).__next__ for it in iterables)

while num_active:

try:

for next in nexts:

yield next()

except StopIteration:

# Remove the iterator we just exhausted from the cycle.

num_active -= 1

nexts = cycle(islice(nexts, num_active))

print(*roundrobin(*lists)) 7、使用切片实现代码语言：javascript复制l1 = ["a","b","c","d"]

l2 = [1,2,3,4]

l3 = ["w","x","y","z"]

l4 = [5,6,7,8]

lists = [l1, l2, l3, l4]

lst = [None for _ in range(sum(len(l) for l in lists))]

for i, l in enumerate(lists):

lst[i:len(lists)*len(l):len(lists)] = l

print(lst)

# demo1

aList = [1,2,3]

bList = ['www', 'jb51.net']

aList[len(aList):len(aList)] = bList

print(aList)

# 输出：

[1, 2, 3, 'www', 'jb51.net']

# demo2

aList = [1,2,3]

bList = ['www', 'jb51.net']

aList[1:1] = bList

print(aList)

# 输出为：

[1, 'www', 'jb51.net', 2, 3]8、使用pandas实现代码语言：javascript复制import pandas as pd

l1 = ["a","b","c","d"]

l2 = [1,2,3,4]

l3 = ["w","x","y","z"]

l4 = [5,6,7,8]

df = pd.DataFrame([l1 ,l2, l3, l4])

result = list(df.values.flatten('A'))

print(result)9、使用numpy.dstack和flatten实现代码语言：javascript复制import numpy as np

l1 = ["a","b","c","d"]

l2 = [1,2,3,4]

l3 = ["w","x","y","z"]

l4 = [5,6,7,8]

print(np.dstack((np.array(l1),np.array(l2),np.array(l3),np.array(l4))).flatten())或者代码语言：javascript复制print(np.dstack((l1,l2,l3,l4)).flatten())10、使用zip() 和 np.concatenate()实现代码语言：javascript复制import numpy as np

l1 = ["a","b","c","d"]

l2 = [1,2,3,4]

l3 = ["w","x","y","z"]

l4 = [5,6,7,8]

l5 = np.concatenate(list(zip(l1, l2, l3, l4)))

print(l5)11、使用zip()和reduce()代码语言：javascript复制import functools, operator

l1 = ["a","b","c","d"]

l2 = [1,2,3,4]

l3 = ["w","x","y","z"]

l4 = [5,6,7,8]

print(functools.reduce(operator.add, zip(l1,l2,l3,l4)))